Question
Asked Nov 1, 2019

Determine the density of air at 32 degrees Celsius and 760 torr. The molar mass of air is 28.9 g/mol. Assume ideal behavior.

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Expert Answer

Step 1

As per the data given in the question,

Density of air, d = to be calculated

Temperature, T = 32C = 32 + 273 K = 305 K

Pressure of air, P = 760 torr

molar mass of air, M = 28.9 g/mol

Step 2

The relation between all the above parameters is for the gas showing ideal behavior is shown as follows:

dR T-P M
here,d density (g/ mL)
T temperature(K)
P = pressure(torr)
M molar mass (g/mol)
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dR T-P M here,d density (g/ mL) T temperature(K) P = pressure(torr) M molar mass (g/mol)

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Step 3

On substituting all the values in t...

dx62.364 x10'mL torr mol K1 x305K 760torr x 28.9 g/mol
760torr x28.9 g/mol
d
62.364 x10 mL torr mol"K-1 X305K
d 1.15x10g/mL
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dx62.364 x10'mL torr mol K1 x305K 760torr x 28.9 g/mol 760torr x28.9 g/mol d 62.364 x10 mL torr mol"K-1 X305K d 1.15x10g/mL

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