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Asked Mar 24, 2020
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Please help.

Determine the magnitude of the resultant of the two forces and its direction, measured clockwise
from the x-axis. (Use parallelogram law and law of sine and cosines) Given that F, = 500 N,
F2 = 300 N, y = 30°, and a = 45°.
У
F2
х
F1
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Determine the magnitude of the resultant of the two forces and its direction, measured clockwise from the x-axis. (Use parallelogram law and law of sine and cosines) Given that F, = 500 N, F2 = 300 N, y = 30°, and a = 45°. У F2 х F1

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Expert Answer

Step 1

Drawing parallelogram for the given system of force –

Mechanical Engineering homework question answer, step 1, image 1

Writing the resultant of two force formula from parallelogram law,

Mechanical Engineering homework question answer, step 1, image 2

 

Step 2

Plugging the values in resultant formula,

Mechanical Engineering homework question answer, step 2, image 1

Hence, the resultant force is 646.255 N.

Step 3

Calculating its direction by law of sine,

Let the resultant makes and angle of beta from F2 force,

Then from one triangle of a parallelogram, applying sine law,

Mechanical Engineering homework question answer, step 3, image 1

Mechanical Engineering homework question answer, step 3, image 2

 

...

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