Question
Asked Nov 9, 2019

Determine the mass of 3.83% AgNO3 solution that contains 29.8 g of AgNO3

_____g solution

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Step 1

Molality is the way to express the concentration of any solution. It can be defined as the number of moles of solute dissolves in 1 kg of the solvent. The mathematical expression for molality can be written as:

Moles of solute
Molaity=
Mass of solvent(kg)
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Moles of solute Molaity= Mass of solvent(kg)

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Step 2

 Mass percent or weight percent of a solution is the mass of the solute by the mass of the solution multiply by 100. The mathematical expression for molality can be written as:

mass of solute
x100
Mass %
Mass of solution
mass of solute
Mass %
-x100
(Mass of solute mass of solvent)
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mass of solute x100 Mass % Mass of solution mass of solute Mass % -x100 (Mass of solute mass of solvent)

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Step 3

Calculate the mass ...

mass of solute
Mass %=
- x100
Mass of solution
29.8g
3.83 %=
- x 100
Mass of solution
29.8g
-x 100
Mass of solution =
3.83
Mass of solution = 778 g
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mass of solute Mass %= - x100 Mass of solution 29.8g 3.83 %= - x 100 Mass of solution 29.8g -x 100 Mass of solution = 3.83 Mass of solution = 778 g

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