Question
Asked Sep 24, 2019
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determine the mass of CuS formed when 100.ml of .100 M H2s and 5.00 ml of .150 M Cu(c2H3O2)2 are reacted. What is the concentration of C2H3O2- in the resulting solution?

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Expert Answer

Step 1

Given the volume and molarity of H2S and Cu(C2H3O2)2. Using these, number of moles of both can be determined.

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Molarity No.of moles Volume(L) No.of moles of H,S=MolarityxVolume(L) 100 -L 1000 0.100Mx 0.01moles No.of moles of Cu (C,H,02), -MolarityxVolume(L) 5 L 1000 0.150Mx -7.5x104 moles

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Step 2

From the equation for the given reaction, it can be seen that one mole of Cu(C2H3O2)2 will give one mole of CuS. Therefore, the number of moles o...

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Cu (C,H,02H,S>CuS+2CH0, +2H No.of moles of CuS- No.of moles of Cu (C,H,02), = 7.5x 104 mol mass No.of moles 1 molar mass massof CuS- No.of molesxmolarmass =7.5x104molx95.611g/mol 0.0717 g Mass of CuS formed=0.0717g

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