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Determine the molar solubility for BaCO, by constructing an ICE table, writing the solubility constant expression, and solving for molar solubility. Complete Parts 1-3 before submitting your answer. NEXT Assume the solution already contains 1.4 x 10 M CO² ions. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. BaCO,(s) Initial (M) Change (M) Equilibrium (M) +2x 2.8 x 10+2x 0 2.8 x 10"-2x 1.4 x 10 1.4 x 10¹+x -1.4 x 10 1.4 x 10¹-x 2.8 x 10¹ 1.4 x 10* + 2x Ba² (aq) -2.8 x 10 1.4 x 10¹-2x 2.8 x 10¹+x CO,”(aq) RESET 2.8 x 10*-x >

Determine the molar solubility for BaCO, by constructing an ICE table, writing the solubility constant expression, and solving for molar solubility. Complete Parts 1-3 before submitting your answer. NEXT Assume the solution already contains 1.4 x 10 M CO² ions. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. BaCO,(s) Initial (M) Change (M) Equilibrium (M) +2x 2.8 x 10+2x 0 2.8 x 10"-2x 1.4 x 10 1.4 x 10¹+x -1.4 x 10 1.4 x 10¹-x 2.8 x 10¹ 1.4 x 10* + 2x Ba² (aq) -2.8 x 10 1.4 x 10¹-2x 2.8 x 10¹+x CO,”(aq) RESET 2.8 x 10*-x >

Chemistry for Engineering Students
Chemistry for Engineering Students
4th Edition
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Lawrence S. Brown, Tom Holme
Chapter12: Chemical Equilibrium
Section: Chapter Questions
Problem 12.113PAE
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Determine the molar solubility for BaCO by constructing an ICE table, writing the solubility constant expression, and solving for molar solubility. Complete Parts 1-3 before submitting your answer. PREV [0] [2x]² 1 [2.8 x 10* - 2x]² [1.4 x 10¹] For BaCO3, the value of Ksp is 5.0 × 10⁹. Using the values from the ICE table (Part 1), construct the expression for the solubility constant, Ksp. Each reaction participant must be represented by one tile. Do not combine terms. [1.4 x 10¹ + x] Ksp Question 5 of 10 [2.8 × 10¹] [1.4 x 10* -x] [1.4 x 104]² 2 [1.4 × 10 + 2x]² [2.8 × 10-41² [1.4 x 10¹ - 2x]² = 5.0 × 10-⁹ [x] 3 [2.8 x 10* + x] [x]² [2.8 x 104 -x] RESET [2x] NEXT [2.8 x 104 + 2x]² > Submit +
Transcribed Image Text:Determine the molar solubility for BaCO by constructing an ICE table, writing the solubility constant expression, and solving for molar solubility. Complete Parts 1-3 before submitting your answer. PREV [0] [2x]² 1 [2.8 x 10* - 2x]² [1.4 x 10¹] For BaCO3, the value of Ksp is 5.0 × 10⁹. Using the values from the ICE table (Part 1), construct the expression for the solubility constant, Ksp. Each reaction participant must be represented by one tile. Do not combine terms. [1.4 x 10¹ + x] Ksp Question 5 of 10 [2.8 × 10¹] [1.4 x 10* -x] [1.4 x 104]² 2 [1.4 × 10 + 2x]² [2.8 × 10-41² [1.4 x 10¹ - 2x]² = 5.0 × 10-⁹ [x] 3 [2.8 x 10* + x] [x]² [2.8 x 104 -x] RESET [2x] NEXT [2.8 x 104 + 2x]² > Submit +
Determine the molar solubility for BaCO by constructing an ICE table, writing the solubility constant expression, and solving for molar solubility. Complete Parts 1-3 before submitting your answer. Initial (M) Change (M) Equilibrium (M) +2x 1 2.8 × 10 + 2x Assume the solution already contains 1.4 × 104 M CO2 ions. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. 0 -2x 2.8 x 104 - 2x BaCO₂ (s) Question 5 of 10 1.4 x 10-4 1.4 x 10¹ + x -1.4 x 10-4 2 1.4 x 104 - x 2.8 × 10-4 1.4 x 10* + 2x Ba²+ (aq) -2.8 x 10-4 3 1.4 x 104 - 2x +X + 2.8 x 104 + x RESET -X NEXT CO3(aq) 2.8 × 104 - x > Submit +
Transcribed Image Text:Determine the molar solubility for BaCO by constructing an ICE table, writing the solubility constant expression, and solving for molar solubility. Complete Parts 1-3 before submitting your answer. Initial (M) Change (M) Equilibrium (M) +2x 1 2.8 × 10 + 2x Assume the solution already contains 1.4 × 104 M CO2 ions. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. 0 -2x 2.8 x 104 - 2x BaCO₂ (s) Question 5 of 10 1.4 x 10-4 1.4 x 10¹ + x -1.4 x 10-4 2 1.4 x 104 - x 2.8 × 10-4 1.4 x 10* + 2x Ba²+ (aq) -2.8 x 10-4 3 1.4 x 104 - 2x +X + 2.8 x 104 + x RESET -X NEXT CO3(aq) 2.8 × 104 - x > Submit +
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