Solve:The average atomic mass for J = 65.96 amu65.96 = 63.9296 ×6.744 + 65.9449 × 90.654 + 67.9113 × M + 66.9154 × (100− (M+6.744+90.654))/10065.96 = 431.1412 + 5978.169 + 67.9113 M + 66.9154 × (2.602−M)/1006596 = MM=The abundance of J−68 is The abundance of J−67 is Determine the percent abundance for J-67 and J-68, given thefollowing data: The average atomic mass for J is 65.96 amu.Atomic %Isotopeweight abundanceJ-6463.9296 6.744J-6665.9449 90.654|J-6766.9154 ??J-6867.9113 ??

We have given four Isotopes of J, so total abundance of these four Isotopes will be 100 % . Thus we…

Determine the percent abundance for J-67 and J-68, given the following data: The average atomic mass for J is 65.96 amu. Atomic % Isotope weight abundance J-64 63.9296 6.744 J-66 65.9449 90.654 |J-67 66.9154 ?? J-68 67.9113 ??

Determine the percent abundance for J-67 and J-68, given the following data: The average atomic mass for J is 65.96 amu. Atomic % Isotope weight abundance J-64 63.9296 6.744 J-66 65.9449 90.654 |J-67 66.9154 ?? J-68 67.9113 ??

Appl Of Ms Excel In Analytical Chemistry

2nd Edition

ISBN:9781285686691

Author:Crouch

Publisher:Crouch

Chapter1: Excel Basics

Section: Chapter Questions

Problem 4P

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Question

Solve:

The average atomic mass for J = 65.96 amu

65.96 = 63.9296 ×6.744 + 65.9449 × 90.654 + 67.9113 × M + 66.9154 × (100− (M+6.744+90.654))/100

65.96 = 431.1412 + 5978.169 + 67.9113 M + 66.9154 × (2.602−M)/100

6596 =

MM=

The abundance of J−68 is

The abundance of J−67 is

Determine the percent abundance for J-67 and J-68, given the
following data: The average atomic mass for J is 65.96 amu.
Atomic %
Isotope
weight abundance
J-64
63.9296 6.744
J-66
65.9449 90.654
|J-67
66.9154 ??
J-68
67.9113 ??

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