Question
Asked Feb 5, 2020
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Determine the pH if a solution that consists of 175.0mL of 0.085M Benzoic acid and 100.0mL of 0.045M Sodium benzoate 

Ka of benzoic acid if 6.3x10-5

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Expert Answer

Step 1

Given information:

Ka of benzoic acid = 6.3 × 10-5.

Benzoic acid = 175 mL of 0.085 M

Sodium benzoate = 100 mL 0.045 M

Thus,

Total volume of solution= 175 + 100= 275 mL

 

Step 2

Since,

Chemistry homework question answer, step 2, image 1

Step 3

As we know:

Chemistry homework question answer, step 3, image 1

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