Determine the point of intersection of the lines γ1 : ¯r1(t) = ⟨3, 2, 1⟩ + t⟨1, 0, 1⟩ and γ2 : ¯r2(s) = ⟨7, −2, −1⟩ + s⟨1, −2, −2⟩ or show there is no point of intersection.

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A: Given that:L1: x-22=y+1-1=z3L2: x+12=y-1=z+23

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A: According to guidelines we solve one question. thanku.

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Q: 3. Show that the lines L1 : x = 2+t, y= 2+3t, z = 3+t and L2:1 = 2+t, y= 3+ 4t, z = 4 + 2t…

A: L1: x =2+t , y= 2+3t , z= 3+t  L2: x =2+t , y= 3+4t , z= 3+t

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A: Method 1:

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Q: Show that the lines with symmetric equations L1 : = = and L2 : 팡!%3D 부 =D 촬 %3D y-3 are skew.

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Q: 5. Find the distance between the point (4, 3, 1) and the line f(t) = (2x - 1, –3y + 1, 2)

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