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Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes tographiteНехn forslowly that the enthalpy change of the process must be obtained indirectly. Determine ASorxnC(diamond)Cgraphite)with equations from the following list:(1) С(diamond) + O,g)(2) 2 CO2(g)CO2(g)2 CO(g)02(g)ДН %—D —395.4 kJ=AH 566.0 k.J+(3) C(graphite)+02(s) -»CO2(g)(4) 2 CO(g)C(graphite)+CO2(g)ДН %3D —393.5 kJAH=-172.5 kJДНovkJoverall

Question
Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to
graphite
Нехn for
slowly that the enthalpy change of the process must be obtained indirectly. Determine A
So
rxn
C(diamond)Cgraphite)
with equations from the following list:
(1) С(diamond) + O,g)
(2) 2 CO2(g)
CO2(g)
2 CO(g)02(g)
ДН %—D —395.4 kJ
=
AH 566.0 k.J
+
(3) C(graphite)+02(s) -»CO2(g)
(4) 2 CO(g)C(graphite)+CO2(g)
ДН %3D —393.5 kJ
AH=-172.5 kJ
ДНov
kJ
overall
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Diamond and graphite are two crystalline forms of carbon. At 1 atm and 25°C, diamond changes to graphite Нехn for slowly that the enthalpy change of the process must be obtained indirectly. Determine A So rxn C(diamond)Cgraphite) with equations from the following list: (1) С(diamond) + O,g) (2) 2 CO2(g) CO2(g) 2 CO(g)02(g) ДН %—D —395.4 kJ = AH 566.0 k.J + (3) C(graphite)+02(s) -»CO2(g) (4) 2 CO(g)C(graphite)+CO2(g) ДН %3D —393.5 kJ AH=-172.5 kJ ДНov kJ overall

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Step 1

Given information:

...
(1)C(diamond)+O2 Co,
AH-395.4kJ
(2)2CO
2)2CO+O
AH-566.0kJ
(3)C (graphite)+O29--Co,
AH -393.5kJ
(4)2CO Cgraphite)+CO 2 AH=-172.5kJ
help_outline

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(1)C(diamond)+O2 Co, AH-395.4kJ (2)2CO 2)2CO+O AH-566.0kJ (3)C (graphite)+O29--Co, AH -393.5kJ (4)2CO Cgraphite)+CO 2 AH=-172.5kJ

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