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Asked Dec 17, 2019
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Radio waves from a star, of wavelength 2.50 3 102 m, reach a radio telescope by two separate paths, as shown in Figure P24.13. One is a direct path to the receiver, which is situated on the edge of a cliff by the ocean. The second is by reflection off the water. The first minimum of destructive interference occurs when the star is u 5 25.0° above the horizon. Find the height of the cliff. (Assume no phase change on reflection.)

Direct
path
Radio
telescope
Reflected
path
Figure P24.13
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Direct path Radio telescope Reflected path Figure P24.13

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Expert Answer

Step 1

The path of the radio waves is,

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di

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Step 2

Write the expression for path difference

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8 = d, – d, = d, (1– sin a) = d, (1– sin (180° – 90° – 20)) = d, (1– sin (90° – 20))

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Step 3

It is assumed that there is no phase change due to reflection at the wa...

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d,(1- sin (90° – 20)) d. = 2(1- sin (90° – 20))

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Wave Optics

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