Question

Asked Apr 15, 2019

Do U.S census bureau conducts annual survey to obtain information on the percentage of the voting age population that is registered to vote. Suppose that 385 employed person and 473 unemployed persons are independently and randomly selected, in that 202 of the employed persons and 185 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers (P1), who have registered to vote, exceeds the percentage of an unemployed workers (P2), who have registered to vote? Use a a significance level of a= 0.1 for the test.

1. compute the value of the test statistic. Round to two decimal places.

2. determine the decision rule for rejecting the null hypothesis Ho. Round the numerical portion to two decimal places.

3. make the decision for the hypothesis test.

Step 1

Given that among 385 employed person 202 are registered to vote and among 473 unemployed person 185 are registered to vote.

Let P_{1} be proportion of registered employed person P_{1} = 202/385 = 0.52

Let P_{2} be proportion of registered employed person P_{2} = 185/473 = 0.39

given level of significance = 0.1

Step 2

Here we perform two proportion Z test.

Null Hypothesis : H_{0} : P_{1 }-P_{2} = 0

Alternative Hypothesis : Ha : P_{1 }-P_{2} > 0

The calculate the test statistic we find the pooled proportion p using the formula shown below. we get P =

Step 3

The test statistic for the two proportion hypothesis Z test is shown below and we plug in v...

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