Dr. Romanoff reported the following in a journal: “F (5, 106) = 10.09, p = .04.” Should Dr. Romanoff state that there are significant differences among the variable means at a .05 alpha level?
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Dr. Romanoff reported the following in a journal: “F (5, 106) = 10.09, p = .04.”
Should Dr. Romanoff state that there are significant differences among the variable means at a .05 alpha level?
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- Dr. Stevenson reported the following in a journal: “F (4, 106) = 10.09, p = .04.” Should Dr. Stevenson state that there are significant differences among the variable means at a .01 alpha level?You obtain a t comp of .975 in a two sample independent t test with alpha at .05. Is it significant?The median pH level of the rain in a certain county, was 4.90. A biologist obtains a random sample of 19 rain dates and obtains the following data. Test the hypothesis that the median pH level has decreased from 4.90 at the alpha= 0.05 level of significance.
- Use the following SPSS output to answer the questions. Use an alpha level of .05: Which variable is the independent variable? Which variable is the dependent variable? What would be the null hypothesis for the chi-square test? What would be the research hypothesis for the chi-square test? Is the chi-square test statistically significant? Should we reject or fail to reject the null hypothesis? What is the appropriate measure of association for this table?We tested to see if people who consumed caffeine had a lower average reaction time than those who didn’t consume caffeine at the alpha = 0.08 level. Assume we found a p-value of 0.5437. Which below would be an appropriate conclusion and interpretation? With an alpha of 0.08, and a p-value of 0.5437, we fail to reject the null and state we have insufficient evidence to support that the true average reaction time of caffeine consumers was less than that of non-caffeine consumers. With an alpha of 0.08, and a p-value of 0.5437, we reject the null and state we have sufficient evidence to support that the true average reaction time of caffeine consumers was less than that of non-caffeine consumers. With an alpha of 0.08, and a p-value of 0.5437, we fail to reject the null and state we have sufficient evidence to support that the true average reaction time of caffeine consumers was less than that of non-caffeine consumers. With an alpha of 0.08, and a p-value of 0.5437, we…A car company claims that their Super Spiffy Sedan averages 31 mpg. You randomly select 8 Super Spiffies from local car dealerships and test their gas mileage under similar conditions. You get the following MPG scores: MPG: 30 28 32 26 33 25 28 30 Does the actual gas mileage for these cars deviate significantly from 31 (alpha = .05)?
- For a set alpha level of .05, a predictor that has a p-value less than or equal to .05 suggests that variations in the predictor's value are related to changes in the outcome (response) variable. True or FalseA sample of 124 kissing couples were observed, with 44 of them leaning their heads to the left. Use these sample data to test whether or not the population proportion of kissing couples who lean their heads to the left differs from 1/3. What is the z and p-value?Given a sample mean of xbar=27 and a population standard deviation of σ=3.5 from a previous study where n=16 values, find the z value and p value. The data indicates that the population mean for the speed of a Belgian Malinois is µ=30 mph, but we think it may be higher based on our data. Test the claim that µ<30 with alpha value of a=0.05.
- An educational psychologist was interested in whether using a student’s own name in a story affected children’s attention span while reading. Six children were randomly assigned to read a story under ordinary conditions (using names like Dick and Jane). Six other children read versions of the same story, but with each child’s own name substituted for one of the children in the story. The researcher kept a careful measure of how long it took (in minutes) each child to read the story. The results are shown in Table 2. Using the 0.05 alpha level, does including the child’s name make any difference? Use all of the steps of hypothesis testing.A random sample of 50 COS students contained 13 that owned an iPhone. A random sample of 200 Fresno State students contained 70 that owned an iPhone. Use these data to test the claim that the proportion of COS students who own an iPhone is the same as the proportion of Fresno State students who own an iPhone at the 0.05 level of significance.The NAEP considers that a national average of 283 is an acceptable performance. Using α = .05, run a two-tail t-test for one sample to test Ho: µ=283 for the 2019 scores. Report the t-obt, df, and p-values. Would you reject the null hypothesis that the 2019 scores come from a population with average 283? If this is the case, does it come from a population from larger or smaller average?