Question
Asked Feb 19, 2020
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Draw all possible stereoisomers for each of the following. Indicate those compounds for which no stereoisomers are possible.

a. 1-bromo-2-chlorocyclohexane b. 2-bromo-4-methylpentane c. 1,2-dichlorocyclohexane d. 2-bromo-4-chloropentane e. 1-bromo-4-chlorocyclohexane f. 1,2-dimethylcyclopropane g. 4-bromo-2-pentene h. 3,3-dimethylpentane i. 1-bromo-2-chlorocyclobutane j. 1-bromo-3-chlorocyclobutane

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Expert Answer

Step 1

a. Asymmetric center is a stereocenter that arises to hydrocarbons if the carbon is bonded to four different groups.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n, in which 'n' is the number of asymmetric centers.

Therefore,

The number of stereoisomers present in given compound is, 2n = 4

Chemistry homework question answer, step 1, image 1

Step 2

b. In the given compound

Chemistry homework question answer, step 2, image 1

There is an asymmetric center on C2 carbon.

The equation for finding Stereoisomers from number of asymmetric centers in compounds is 2n in which 'n' is the number of asymmetric centers.

Therefore,

The number of stereoisomers present in given compound is,

21 = 2

Chemistry homework question answer, step 2, image 2

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