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dr/dθ= cos (-5πθ), r(0)=9

Question

dr/dθ= cos (-5πθ), r(0)=9

check_circleAnswer
Step 1

Given,

dr
= cos(-57n0)
d0
To write an expression for r, separate the terms and integrate both sides
dr cos(-50)d0
Jar = fcos(-5n0)d0
-sin(-50)
r =
-+ C
-57T
help_outline

Image Transcriptionclose

dr = cos(-57n0) d0 To write an expression for r, separate the terms and integrate both sides dr cos(-50)d0 Jar = fcos(-5n0)d0 -sin(-50) r = -+ C -57T

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Step 2

Use the initial condition i.e. r(0...

-sin-5(0))
9 =
- +c
-57%
9 0+c
c 9
help_outline

Image Transcriptionclose

-sin-5(0)) 9 = - +c -57% 9 0+c c 9

fullscreen

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Math

Calculus

Integration

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