Question
Asked Dec 12, 2019
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Due Thu 12/1272019 11:59 pm
Assume that a sample is used to estimate a population proportion p. Find the 99 9% confidence interval for a sample of
size 353 with 27% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents)
accurate to three decimal places.
CI=
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Due Thu 12/1272019 11:59 pm Assume that a sample is used to estimate a population proportion p. Find the 99 9% confidence interval for a sample of size 353 with 27% successes. Enter your answer as an open-interval (i.e., parentheses) using decimals (not percents) accurate to three decimal places. CI=

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Expert Answer

Step 1

From the given data,

Population proportion = 27%

Sample size=353

Step 2

Formula for confidence interval for population proportion is,

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CI = p+E here, p =population proportion = 27% =0.27 P(1-p) E= margin oferror = Zx for 99.9% confidence level,z-value is 3.291

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Step 3

Margin of er...

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p(1-p) E = Zx 0.27(1-0.27) =3.291x 353 =3.291x0.0236295768 =0.0777649373 E = 0.078

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