Question

Asked Dec 2, 2019

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Find or evaluate the integral by completing the square. (Use *C* for the constant of integration.)

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Step 1

Let's look at the denominator.

The denominator = 9x^{2} – 18x + 36 = 9x^{2} – 18x + 9 + 27 = (9x^{2} – 18x + 9) + 27 = 9[(x^{2} – 2x + 1) + 3] = 9[(x – 1)^{2} + 3]

Step 2

Please see the white board. Let x - 1 = z; hence, dx = dz

The integral therefore takes the shape as shown in the last expression on the white board.

Step 3

Recall the standard integration ...

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