E 450 kN A K N H 40 m 40 m 40 m 40 m 26 m 13 m 3. 26 m 26 m

Q: 3 m 2 m B 4 m F A 30 kN 18 kN

A:

Q: F = 375 Ib F = 500 Ib B. 8 ft 6 ft 5 t- 30 F = 160 lb

A: given cantilever beam as shown below

Q: 10) ΣF,- EF, = 0 N a= FN = 40 N 800 A- 30 35 N 80 kg FN

A:

Q: D 1500 N 4 m 2000 N E 4 m B A 6 m

A:

Q: 20 KN 10 KN 10KN/m 15KN/m 10 KN/m B. 1.00 1.00 2.00 1.00

A:

Q: س )1( : اذا كانت منظومة القوى المبينة بالشكل )1( 60 هي منظومة متزنة ، احسب القوة T والزاوية 0 20 lb…

A:

Q: 10 kN 5 kN 3 kN/m F C D E 3 m 1 m 4 m 3 m 1 m

A:

Q: A hydraulic cylinder has a 750 mm diameter. How much force (kN) can be developed with 275 kPa oil…

A: Given    Pressure, P = 1275 kPa  Diameter, d = 750 mm                     = 0.75 m Find   Force…

Q: What is the pressure at the center of plpe B (kPa)? Group A Group B B water water mercury S-133…

A:

Q: Sm 8 m/s 15m 0 AI 6 m/s

A:

Q: Blood pressure is 80 mm Hg . Convert it into absolute pressure? (1 atm = 760 mm Hg)

A: Absolute pressure is the sum of gauge pressure and atmospheric pressure.  Pabs = Pg + Patm where…

Q: 10 MPa - 30 MPa 70 MPa 70 MPa 30 MPa 10 MPa a) 20MPa b) -20 MPa c) 63,54MPa d) -63,54MPa e) 40 MPa

A:

Q: AP W h mg ΔΡ + Az +

A: The above given equation is Bernoulli's equation. Every term of Bernoulli's equation has units of…

Q: 70 m/s 60 m A 30 km/h В 2.5 m 350 m

A:

Q: 166 kN HOKM 2 bokN 4m 4m 2m 4mi 3m 3m

A: In step 1 we draw given diagram and calculate reaction forces:-

Q: 1.5 m 2 m 4 m Fc= 40 N Fn= 55 N 6 m 3 m 4m

A:

Q: 12 kN.m 3 m 12 kN/m 1 m 12 kN.m 1 m 4 m 3 m 12 kN/m

A: The shear force and bending moment diagram has been drawn below.

Q: KIN 14 kN / m 10 kN / m A B ID 4 m 2.5 m 2.5 m 3 m

A: Finding support reactions:RA+RB=12*4*14+14*5+20+30RA+RB=148…

Q: 40 kN/m B 8 m 2 m

A: Linear deviation of the longitudinal axis of the beam is known as deflection whereas angular…

Q: 3 kN/m В 8 m 4 m D 10 m 5 kN H. = 5 kN A A M, = 66 kNm a Va= 24 kN

A:

Q: What is the force resisted by member DE? C В D 6 m 4 m 4 m E A 6 m H 6 m G 6 m F 6 m 140 kN 110 kN…

A:

Q: 10 kN 4 Smart 3 soi non 12 kN 8 kN 6 kN Aqu.21 Azn Iml F

A: Given

Q: 20 kN 40 kN 10 kN/m 1 m 2 m 2 m 2 m 1 m w

A: Before going through the calculation for shear force and bending moment calculation first, calculate…

Q: Fg= 900 N A Fc= 600 N 6 m 3 m 45 B 45m 6m

A:

Q: 15 KN 10 KN 10 KN 20 KN E A 5.0m

A: To determine the support reaction at J.

Q: 6 kN 9 kNm 4 kN/m E 2 m 0.5 m 0.5 m 2 m

A:

Q: 2 tór/m 8 ton F 4 ton-m E 3 ton/m 2 m 4 m Im1m 2 m 2 m

A: According to the principal of engineering mechanics  Reaction and moment at support is equal to zero

Q: 6 KN 5 kN 4 kN 4 kN 5 kN, K 3 kN 4 m 2 kN HA A G |B C |D F 2 m 2 m 2 m T 2 m T 2 m T 2 m

A:

Q: 96 30 lb/ft 180 Ib · ft - 9 ft - 4.5 ft M (lb · ft) 200

A:

Q: What is the pressure at the center of plpe B (kPa? Group A Group B B water water mercury S-133…

A:

Q: ‘Hydraulic lift’ works on the basis of

A:

Q: 1. The unit of joule can be converted to which of the following? (A) Pa-m2 (B) N . kg (C) Pa/m? (D)…

A: The unit of Joule can be converted into Pa.m3. Therefore, option (D) is the correct option.

Q: F = 120 lb | 30° 12 kN 1.25"- 30 4 m 1.5" 5 m 11"

A:

Q: MTTR

A: solution given below

Q: 12 KN 2.5 KN/M 介介企 A 12 m B 4m

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: Which case shows the least acceleration? 20 lb 15 lb A 45° 45° 45° E 15 Ib

A: GIVEN:

Q: 4 kN E В F 3 m A L K J IH 12 m, 6 @ 2 m A B 15.781kN 14.908KN 13.334kN

A:

Q: RB 50KN bm 100 KN 4m B 4m

A:

Q: Blood pressure is 110 mm Hg . Convert it into absolute pressure? (1 atm = 760 mm Hg)

A: Absolute pressure is the sum of gauge pressure and atmospheric pressure. Pabs=Pg+Patm Here, Pg is…

Q: |20 kN 15 kN/m A 2 m 4 m B.

A: The reactions on the supports of beam can be drawn as follows,

Q: members DE, DJ, EJ, and IJ. 2 KN XNK 8m 8m 8m 8m L K J H 1 kN 8m 3 KN 1.5m 2m 8m

A: To find force in member DE,DJ,EJIJ

Q: 20 kN D 20 kN 20 kN 3 m 10 kN 3 m 3 m A 4 m 4 m E 4 m 4 m B,

A:

Q: P P=3,000 lb W=200 lb/ft Rz 8 ft 18 ft Ri 6 ft

A: Draw free body diagram of beam and convert uniformly distributed load into point load

Q: Deter mile State spo ce rehg1esentection O/p > 3) 4Nm 3N-m 3N/p fits + 3 kg 3 N/m 3N-S/m 2 N-5/m…

A:

Q: 1000 kg. 400 kg D BV 3m 1.5m * 1.5m 6m R R2

A:

Q: F126KN 180KN 26 -3m 1.5m 48 65° 145KN V165 KN

A: Drawing the system of force as shown below – Let us take point A as an origin of the coordinate…

Q: 3 m 6 m A 400 N C 300 N x' 2 m B

A: For solution refer below images.

Q: E D 1 m A F F 1m 1 m

A:

Slope and Deflection

The slope in a deflected beam is described as an angle in radians made by the tangent of the section with the original axis of the beam. The deflection at any point on the axis of the beam is defined as the lateral displacement of the point before and after loading.