E A 35° = 0.45 a M₂² = B D no friction W₁ = 6 16 W₂ Wa с 12 16 8 16² P = TBD Three blocks are connected by two cords, and are arranged as shown above. achieves Velocity of VA (The pulleys are frictionless Assuming that the blocks start at rest, find the horizontal force P (see diagram) that is required in order that Block A 16 ft/s (mag) after 2.5s. Assume that the tensions T, and T₂, in cords AB and BC respectively, Use the Principle of Impulse and Momentum. You will need to use Newton's Second Law to first find the normal reaction on Block A. Hint: You will need to apply PIM individually to each block. ,are constant.

A system of a 50 kg empty trolley and a 140 kg counterweight is shown in Figure below. After the counterweight has dropped 10 m from rest, the velocity of the trolley is 6 m/s. If all frictional resistances can be regarded as a single force F acting on the trolley parallel to the inclined plane, calculate the resistance of the force. Note that pulleys are smooth and frictionless.

The mB = 8 kg block is moving to the right with a velocity of vo = 0.96 mls on a horizontal surface when a force P is applied to it at time t = 0 as shown in the following figure. The coefficient of kinetic friction between the block and the surface is Hk = 0.27. Use P = 38, P2 = 72, t1 = 0.15, t2 = 0.35. %3D Р, N P2 P mB P1 t, s t1 t1 Calculate the velocity v in m/s of the block when t = 0.35 s. Insert your answer correct up to at least a third decimal place.

Solve problem 4 pls