Each copper(II) sulfate unit is associated with five water molecules in crystalline opper(II) sulfate pentahydrate (CuSO4 ⋅ 5H2O). When this compound is heated in air above 100oC, it loses the water molecules are also its blue color: CuSO4 ⋅ 5H2O → CuSO4 + 5H2O If 9.60 g of CuSO4 are left after heating 15.01 g of the blue compound, calculate the number of moles of water originally present in the compound.
Each copper(II) sulfate unit is associated with five water molecules in crystalline opper(II) sulfate pentahydrate (CuSO4 ⋅ 5H2O). When this compound is heated in air above 100oC, it loses the water molecules are also its blue color: CuSO4 ⋅ 5H2O → CuSO4 + 5H2O If 9.60 g of CuSO4 are left after heating 15.01 g of the blue compound, calculate the number of moles of water originally present in the compound.
General Chemistry - Standalone book (MindTap Course List)
11th Edition
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Chapter3: Calculations With Chemical Formulas And Equaitons
Section: Chapter Questions
Problem 3.128QP: Copper reacts with nitric acid according to the following reaction....
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Each copper(II) sulfate unit is associated with five water molecules in crystalline opper(II) sulfate pentahydrate (CuSO4 ⋅ 5H2O). When this compound is heated in air above 100oC, it loses the water molecules are also its blue color:
CuSO4 ⋅ 5H2O → CuSO4 + 5H2O
If 9.60 g of CuSO4 are left after heating 15.01 g of the blue compound, calculate the number of moles of water originally present in the compound.
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