Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aqueous, mildly alkaline suspension of magnesium hydroxide formulated at 8.0 % (w/v). It would take ________ mL of milk of magnesia to titrate the stomach acid produced in each day. (Mg(OH)2 molar mass = 58.32 g/mol) Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aqueous, mildly alkaline suspension of magnesium hydroxide formulated at 8.0 % (w/v). It would take ________ mL of milk of magnesia to titrate the stomach acid produced in each day. (Mg(OH)2 molar mass = 58.32 g/mol)  Page 3 of 4  Name:_________________________________CHM 1020 W9 Lab

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Asked Oct 29, 2019
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Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aqueous, mildly alkaline suspension of magnesium hydroxide formulated at 8.0 % (w/v). It would take ________ mL of milk of magnesia to titrate the stomach acid produced in each day. (Mg(OH)2 molar mass = 58.32 g/mol)

 

Each day, the stomach produces 2.0 L of gastric juice that contains 0.10 M HCl. Phillips Milk of Magnesia is a white-colored, aqueous, mildly alkaline suspension of magnesium hydroxide formulated at 8.0 % (w/v). It would take ________ mL of milk of magnesia to titrate the stomach acid produced in each day. (Mg(OH)2 molar mass = 58.32 g/mol)

 

 

Page 3 of 4

 

 

Name:_________________________________CHM 1020 W9 Lab

 

 

 

 

 

 

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Expert Answer

Step 1

Given that the volume of gastric juice produced is 2L.

The molarity of HCl present in gastric juice is 0.10 M.

So, the no. of moles of HCl = volume of HCl × molarity of HCl

Thus no. of the mole of HCl = 2 × 0.10

no. of the mole of HCl = 0.20 moles.

Step 2

When HCl react with magnesium hydroxide, this is shown by equation (1)

Also given that 8% of (w/v) milk of magnesium that means 8 g of magnesium hydroxide are present in 100 ml of solution.

The molecu...

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2 HCl Mg(OH)22H,0+M8CL given mass molecular mass no. of moles (n) = 8g 58.32 gmol =0.1371 mole

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