Question
Asked Oct 24, 2019
Each side of a square is increasing at a rate of 3 cm/s. At what rate is the area of the square increasing when the area of the square is 64 cm2?
cm2/s
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Each side of a square is increasing at a rate of 3 cm/s. At what rate is the area of the square increasing when the area of the square is 64 cm2? cm2/s

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Step 1

Given:

Each side of a square is increasing at a rate of 3 cm/s. At what rate is the area of the square increasing when the area of the square is 64 cm2?

Step 2

The given information can be seen from the below figure.

dl
3cm /s
dt
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dl 3cm /s dt

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Step 3

So, from the figure and given...

Area of square 64cm
dl
= 3 cm/ sec
dt
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Area of square 64cm dl = 3 cm/ sec dt

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Calculus

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