Question
Asked Oct 6, 2019

A pump that has the characteristic curve shown in the accompanying graph is to be installed as shown. What will be the discharge of water in the system? [Assume kb = 0.3 for the bend; also, assume the entrance is bell-mouthed, not re-entrant]

Elevation
20 ft
L 50 ft
D 10 in
f- 0.020
L 950 ft
D= 10 in
f= 0.020
r/d 1
Elevation
15 ft
Elevation 10 ft
T= 60°F
80
60
t
40
Pump curve
20
1000 2000 3000 4000 5000
Q, gpm
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Elevation 20 ft L 50 ft D 10 in f- 0.020 L 950 ft D= 10 in f= 0.020 r/d 1 Elevation 15 ft Elevation 10 ft T= 60°F 80 60 t 40 Pump curve 20 1000 2000 3000 4000 5000 Q, gpm

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check_circleExpert Solution
Step 1

Given information:

We have the following information from the diagram.

Elevation 20 ft
L 50 ft
D 10 in
f=0.020
L-950 ft
D 10 in.
f0.020
rid 1
Elevation 15 ft
Elevation 10 ft
T 60 F
80
60
40
Pump curve
20
1000 2000 3000 4000 5000
Q. gpm
help_outline

Image Transcriptionclose

Elevation 20 ft L 50 ft D 10 in f=0.020 L-950 ft D 10 in. f0.020 rid 1 Elevation 15 ft Elevation 10 ft T 60 F 80 60 40 Pump curve 20 1000 2000 3000 4000 5000 Q. gpm

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Step 2

Calculation:

For the above system we can apply Bernoulli’s principle at the surface of the reservoirs.

That is,

-+2+
Pg 2g
++h
Pg 2g
0+0+10+0.020x 50 x V0.020x 950 x V*0+20+ h
10
2x32.2x
12
10
2x32.2x
12
0.020x50xV 0.020x 950 x V-10 = h
10
2x32.2x
12
10
2x32.2x
12
0.018V2+0.354 -10= h
h (0.018+0.354)v2 -10
h(0.372)2-10..
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-+2+ Pg 2g ++h Pg 2g 0+0+10+0.020x 50 x V0.020x 950 x V*0+20+ h 10 2x32.2x 12 10 2x32.2x 12 0.020x50xV 0.020x 950 x V-10 = h 10 2x32.2x 12 10 2x32.2x 12 0.018V2+0.354 -10= h h (0.018+0.354)v2 -10 h(0.372)2-10..

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Step 3

We have a relation between disch...

Q AxV
V
A
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Q AxV V A

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