Question
Asked Mar 19, 2020
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From the following data,
 
C(graphite) + O2(g

 CO2(g)

 
Δ

H

o
 
rxn

 = −393.5 kJ/mol
 
H2(g) + 

1
 
2

O2(g

 H2O(l)

 
Δ

H

o
 
rxn

 = −285.8 kJ/mol
 
2C2H6(g) + 7O2(g

 4CO2(g) + 6H2O(l)

 
Δ

H

o
 
rxn

 = −3119.6 kJ/mol
 
calculate the enthalpy change for the reaction below:
 
2 C(graphite) + 3H2(g

 C2H6(g)
 

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Expert Answer

Step 1

Given:

∆H1= -393.5 kJ/mol

∆H2= -285.8 kJ/mol

∆H3= -3116.6 kJ/mol

Step 2

To determine the enthalpy change for given reaction:

Chemistry homework question answer, step 2, image 1

Step 3

Chemistry homework question answer, step 3, image 1

...

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