Equal moles of sulfur dioxide gas and oxygen has are mixed in a flexible reaction vessel and then sparked to initiate the formation of gaseous sulfur trioxide. Assuming that the reaction goes to completion, what is the ratio of the final volume of the gas mixture to the intial volume of the gas mixture if the volumes are measured at the same temperature and pressure.

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Asked Oct 18, 2019
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Equal moles of sulfur dioxide gas and oxygen has are mixed in a flexible reaction vessel and then sparked to initiate the formation of gaseous sulfur trioxide. Assuming that the reaction goes to completion, what is the ratio of the final volume of the gas mixture to the intial volume of the gas mixture if the volumes are measured at the same temperature and pressure. 

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Expert Answer

Step 1

The reaction of sulfur dioxide (SO2) with oxygen (O2) is as follows:

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2SO2+022SO3

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Step 2

Let us assume n moles of each SO2 and O2 is present initially. According to the reaction, two moles of SO2 reacts with one mole of O2 to produce two moles of SO3. So, n moles of SO2 reacts with 0.5n moles of O2 to produce n moles of SO3.

Step 3

The initial moles of gas (ni) is calculated using equation (1) in which n1 is the moles ...

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(1) = nn = 2n

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