Ethyl lodide decomposes at high temperatures according to the reaction shown here: C2H5I(g) - C2H4(g) + HI(g) --> The concentration of ethyl iodide is followed over time and shown in the table below- Time(min) [C2H5I] (M) 0. 0.36 15 0.30 30 0.25 45 0.19 60 0.13 Determine the order of the reaction and the rate constant.

Chemistry: Principles and Reactions
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Chapter11: Rate Of Reaction
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Problem 35QAP: Azomethane decomposes into nitrogen and ethane at high temperatures according to the following...
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Ethyl lodide decomposes at high temperatures according to the reaction shown
here:
C2H5I(g) --> C2H4(g) + HI(g)
The concentration of ethyl iodide is followed over time and shown in the table
below-
Time(min) [C2H51] (M)
01
0.36
15
0.30
30
0.25
45
0.19
60
0.13
Determine the order of the reaction and the rate constant.
Transcribed Image Text:Ethyl lodide decomposes at high temperatures according to the reaction shown here: C2H5I(g) --> C2H4(g) + HI(g) The concentration of ethyl iodide is followed over time and shown in the table below- Time(min) [C2H51] (M) 01 0.36 15 0.30 30 0.25 45 0.19 60 0.13 Determine the order of the reaction and the rate constant.
a.
1st order, k=0.014 min
1
Ob.
Ob. I get a different answer.
C.
2nd order, k-0.0042 M-1min1
Od. oth order, k=120 M/min
Transcribed Image Text:a. 1st order, k=0.014 min 1 Ob. Ob. I get a different answer. C. 2nd order, k-0.0042 M-1min1 Od. oth order, k=120 M/min
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