Ethylene oxide is formed by the partial oxidation of ethylene. Unfortunately some of the ethylene is completely oxidized to form CO2 and H2O. The reactions are2C2H4 + O2 --> 2C2H4O (desired product)C2H4 + 3O2 --> 2CO2 (undesired product) + 2H2OA feed stream comprised of 16 moles C2H4 and 100 moles O2. 25% of the ethylene is converted with a yield of 75% (Defined by mole C2H4O/mol C2H4 reacted).a. Draw a schematic of this processb. Find the output of the reactor.c. What is the selectivity of the process

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Asked Feb 17, 2019
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Ethylene oxide is formed by the partial oxidation of ethylene. Unfortunately some of the ethylene is completely oxidized to form CO2 and H2O. The reactions are

2C2H4 + O2 --> 2C2H4O (desired product)

C2H4 + 3O2 --> 2CO2 (undesired product) + 2H2O

A feed stream comprised of 16 moles C2H4 and 100 moles O2. 25% of the ethylene is converted with a yield of 75% (Defined by mole C2H4O/mol C2H4 reacted).

a. Draw a schematic of this process

b. Find the output of the reactor.

c. What is the selectivity of the process

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Expert Answer

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Step 1

Part (a)

 

The schematic diagram of the given process is shown below.

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Step 2

Part (b)

 

25% ethylene is converted. Thus,

Moles of C2H4 reacted = (0.25*16) = 4 mol

Moles of C2H4 unreacted, n1 = (16-4) = 12 mol

The yield is given as 75%. Thus,

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Step 3

From the stoichiometry of the desired reaction, 2 mol C2H4O is formed from 2 mol of C2H4 and 1 mol O2. Therefore, 3 mol C2H4O is formed from 3 mol of C2H4 and 1.5 mol O2.

Moles of C2H4 reacted by undesired reaction is = (4-3) = 1 mol

From the stoichiometry of the undesired reaction, 1 mol C2H4 reacts with 3 mol O2 to form 2 mol of CO2 and 2 mol of H2O. Therefore,

 

Moles of CO2 formed is, n4 = 2 mol CO2

M...

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