Evaluate sec(4x) tan(4x)dx Select one: sec(4x) a. +C sec(z) b. +C 4 C. sec(4x) + C d. 4 sec(4x) + C

Q: D₂ tan³ x = 3 sec O 3 tan² z O secr O 3 tan² z sec²

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Q: dy tan5 2x sec4 2x %3D

A: NOTE: Refresh your page if you can't see any equations. . use the formula  ................(1)

Q: Integrate the function by using trigonometric substitution. dx, x < 2

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Q: - sin² ydy 6. 4 tan" y

A: As per the guidelines I can solve only first question

Q: dx 9x2-2

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A: The integration of a function with respect to x over an interval gives us the area between the curve…

Q: Cos X. is iF C3)?

A: Given,            Consider the function Fx whose second derivative is F''x=18x+3cosx.           Also…

Q: (tan*Vx ) (sec²vx ) dx . b) Evaluate

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Q: How would you evaluate∫sec12 x tan x dx?

A: Consider the following integral: Consider the following equation as shown in below:

Q: b) f(x) = tan (VInx) %3D

A: f(x)=tan^-1(sqrt(lnx))

Q: (a) Find fx5 +2 cos(2x) dx

A:

Q: Evaluate. dx 2+e (а) -2x tan Vr (b) dx 10x2 dx (c) /1-x²

A: To solve , these problems , we use substitution method of integration and proceed.

Q: S tan?(-2t) sec²(-2t)dt

A: Given, ∫tan2(-2t)sec2(-2t)dt

Q: dx XVx*-1 Select one: a. -1 sec-(x) + C b. sec-(x2) + C

A: Integration Question

Q: Let f(æ) = - 6 sin(x)cos(x). %3D df dx d²f da?

A: Using product rule, (uv)'= u'v + v'u Here we take, u = sinx v = cosx df/dx =(uv)'…

Q: Evaluate tan' x sec* x 3 x dx. Use the substitution u = tan x.

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Q: calculate y" : y = tan(x2)

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Q: Find, tan(x / 2)dx A) (1/2) sec (x/2)+c C) 2 sec (x/2)+c B) 2m sec(x/ 2)+c D) (1/2n sec(x/2) +c

A: Given that a integration of tan(x/2) and we solve it by using general formulas of integration. We…

Q: Evaluate f sin (2(V1-) dx

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Q: Differentiate. y = 7x2 sin x tan x y' =

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Q: 2x-1 dy if y=f and f(x)=sinx²,find X

A: see 2nd step

Q: If f(x) = 2x(sina + cos a), find f'(x) = %3D

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Q: Find dy y= cof ( + tan)

A: Given : y = cot-12x+tan-1x2

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A: Using method of linear differential equation.

Q: y = 5x – 6 tan x, concave upward concave downward

A: Given problem:- y=5x-6tan(x) , (-π/2, π/2)  Determine the open intervals on which the graph is…

Q: Find ∫ tan5 x dx

A: To integrate: ∫tan5xdx.  Given integral can be written as: ∫tan5xdx=∫sin5xcos5xdx Let substitute…

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A: I=∫tan3(x)sec2(x)dxsubstitute  tanx=udiffrentiatesex2xdx=du

Q: Find for y = sec(x)

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Q: y = sec² x tan(2x)

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Q: Show ;) d Sec x = Secx tanx D d csCX = -CSCX Cott

A: we can show it by first principal

Q: Evaluate tan |2x| dx F

A: The given definite integral,    ∫-π8π6tan2xdx

Q: d dx tan x = sec² x

A: According to Bartleby guidelines we can only solve 1 question

Q: T/3 tan x dx sec x

A: Given integral: ∫0π3tan3xsecxdx We know that, sec2x-tan2x=1, and ddxsecx=secxtanx.

Q: l6X-tan 3X, (- find openint & concav f(x)= 6-(seč 3x)3 3 sec?

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Q: Integrate the given function. T/ 20 2 sec 5x -dp- 4 + tan5x 1/20 2 sec 5x 1 5 -In 4 - 4 + tan5x | LO

A: The given integration is:

Q: dx 1+tan x

A:

Q: 1 x³ -1 y =e*(dsin 3x- tanx')+- 10 y' = ? (fx +1)

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Q: Q5 sinx e -dx- tanxcscx a) esinx + C ( b cosX + C c) e tanx + c ( d COSX מ + c secx

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Q: Q3/ find y' x+ tan 4 x y = sec x

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Q: Calculate tan x ( sec“ x ) dx using u-substitution with: (i) u = tan x (ii) u = sec x

A: I have stated the used formulas in the solution.

Q: Evaluate. 1 (a) [ 4x³ + dx 4x3 (b) | sec x(tan x+cos x) dx (c) [ : - 2e* dx

A: As per our guidelines we are suppose to solve only first three sub-parts of a question. Kindly…

Q: Calculate y". y = tan(x2)

A: First of all, consider the formula for the chain rule and the given function y. Then assume u and v…

Q: Find y' for the following e+ tan(e*)= y secx Select one: secx tanx- sec2(e*) - secx -y secx tanx+…

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Q: Differentiate the following x 2 tan(y) + y 10 sec(x) = 2x

A: Given that

Q: B1. By using substitution method, evaluate [5 tan x sec² x dx.

A: To solve the given integral using substitution