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Evaluate sin(3x) dx.sin(3x) dx(Use C as the arbitrary constant.)

Question
Evaluate sin(3x) dx.
sin(3x) dx
(Use C as the arbitrary constant.)
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Evaluate sin(3x) dx. sin(3x) dx (Use C as the arbitrary constant.)

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Step 1

sin5(3x) = sin4(3x).sin(3x) = [1 – cos2(3x)]2sin(3x)

Step 2

Let cos(3x) = z

Hence, -3sin(3x)dx = dz

Hence, Integrand = sin5(3x)dx  = [1 – cos2(3x)]2sin(3x)dx = - (1 – z2)2dz / 3

Step 3

Please see the wh...

1
sin (3r)dar
5
dz
3
223
+
3
--c
1
/1-22+d=-
+C
Z
3
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1 sin (3r)dar 5 dz 3 223 + 3 --c 1 /1-22+d=- +C Z 3

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Tagged in

Math

Calculus

Integration

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