Evaluate the indefinite integral 6 dx %| x2 Vx2 + 9

Q: Find the indefinite integral.

A: To Find the indefinite integral. Substitution  u = x3 du = 3x2 dx du/3 = x2 dx

Q: Find the indefinite integral.

A: We find this indefinite integral by the method of substitution. We re-write the integral in a…

Q: e2x dx 10. V1+e2x

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Q: Find the indefinite integral.

A: We have to evaluate the following integral: ∫x2-3x+2x+1dx

Q: Find the indefinite integral ∫(x+√x)2 dx.

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Q: Find the indefinite integral.

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Q: Evaluate the integral. '2 (x - 8|x|) dx -1

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Q: Find the indefinite integral x + 3 dx x + 6x + 7 9.

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Q: Find the indefinite integral. x + 8x + 1 dx *+ 12x2 + 3x + 2

A: The given integral,∫x2+8x+1x3+12x2+3x+2dx

Q: Evaluate the indefinite integral. x + 4 dx x2 + 8x + 17

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Q: Find the indefinite integral ∫ e−x4(−4x3) dx

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Q: 4. dx 4x. e+x-7

A: Solved below...

Q: Find the indefinite integral.

A: Our Aim is to evaluate the following indefinite integral given below:-∫x3-8xx2dx -(i)

Q: Find the indefinite integral ∫ (x2 + 8) /x√(x2 − 4)  dx

A: Given that: The indefinite integral ∫x2 + 8xx2 - 4 dx

Q: Evaluate the integral. 3 x - 3 dx 11 X

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Q: dx (x+5)+9

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Q: Find the indefinite integral. ∫x(x2 + 1)2 dx

A: We have to find the indefinite integral: ∫xx2+12dx We will solve this integrals using substitution…

Q: Find the indefinite integral. x2 + 4x +3 dx x+ 6x2 + 9x +8

A: Given : Indefinite integral ∫x2 + 4x + 3x3 + 6x2 + 9x + 8dx   To find : Solution of given integral…

Q: Find the indefinite integral ∫ x /(x2 − 3) dx

A: we have to find the integral  ∫xx2-3dx

Q: Find the indefinite integral. x² + 4x +3 dx x3 + 6x2 + 9x + 8

A:

Q: Find the indefinite integral.

A: To find: The indefinite integral of ∫1x231+x13dx. Formula used: ∫afxdx=a∫fxdx ∫1xdx=ln x+C

Q: Find the indefinite integral.

A: Given integral: ∫x2-2xx3-3x2dx

Q: find the indefinite integral 3x^2(x^3+1)^6 dx

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Q: Find the indefinite integral.

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Q: Evaluate the integral ∫x(x - 1)10 dx

A: the given integral is: ∫xx-110dx let the given integral be I. therefore, I=∫xx-110dx substitute…

Q: Evaluate the integral. x³ - 6 dx +ク 11 X

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Q: Find the indefinite integral.

A: Given:          ∫x2+2x-6x4dx Expand: x2+2x-6x4=1x2+2x3-6x4 Apply the sum rule: ∫fx±gxdx=∫fxdx±∫gxdx…

Q: Find the indefinite integral ∫ dx / √x(2√x + 5)

A:

Q: Evaluate the indefinite integral:  x3ln(x2-1)dx

A: Given integral By using the following substitution, we get

Q: 3x dx x +x-6 2

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Q: Find the indefinite integral. x² + 4x + 3 dx x3 + 6x2 + 9x + 8

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Q: Find the indefinite integral. x + 7x2 + e) dx

A: The sum rule of integration states that ∫a+bdx=∫a dx+∫b dx. The constant rule of integration states…

Q: Find the indefinite integral ∫(3√x+e3)dx.

A:

Q: Find the integral ∫(x3 + x)5(3x2 + 1) dx.

A: we have to find the integral of ∫(x3 + x)5(3x2 + 1) dx.

Q: Evaluate the indefinite integral. -х —13 dx x+x-6 .2

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Q: Find the indefinite integral ∫(x2 − 3x + 2) / (x + 1) dx

A: Given: The indefinite integral, ∫x2-3x+2x+1dx.

Q: Find the indefinite integral ∫ 1/x√(x4 − 4) dx

A: To evaluate integral : ∫1xx4-4dx By using substitution method,  Take t = x2  dt = 2x dx dt2x=dx

Q: Find the indefinite integral. x° - 5x xp. 4 X° - 5x dx = 4

A: The given integral is ∫x5-5xx4dx

Q: Find the indefinite integral. ∫(x2 + 2x − 6)/ x4 dx

A: Consider the integral: I=∫x2+2x-6x4dx……1

Q: Vx2 – 4 dx x2

A:

Q: Find the indefinite integral. x2 + 4x + 3 dx x³ + 6x2 + 9x + 6

A: Here we have to solve integral equation by substitution.

Q: Evaluate the indefinite integral dx x(x²+2x+1)

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Q: Find the indefinite integral. x² + 4x + 5 dx x3 + 6x² + 15x + 8

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Q: Find the indefinite integral. ∫e3x+1 dx

A: The given integral is ∫e3x+1 dx

Q: Find the indefinite integral ∫(x4 + 5x) dx

A: Given: ∫(x4 + 5x) dx Now by using the sum rule, ∫fx±gxdx=∫fxdx+∫gxdx⇒∫x4dx+∫5xdx

Q: Find the indefinite integral. ∫ 6/ 3√x dx

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Q: Find the indefinite integral ∫( x3 + x + 1)/( x4 + 2x2 + 1) dx

A: Assume the given integral be I, rewrite it. Break the integral in two parts.…

Q: * (x² + 4)³/2 -dx

A: Find the integral of the give function: ∫x2+432xdx

Q: Evaluate the integral. integral    10/ (x-1) ( x2  + 9) dx

A: Explanation: We need to find that,  ∫10(x-1)(x2+9)dx Take constant out 10∫1(x+1)(x2+9)dxUsing…