Can i get help with this problem step by step?
Evaluate the integral. In 5 2х dx Зе 0 In 5 | Зе 2X dx 3D 0
To evaluate the below integral
x=In(5) 3e2 dx Jx=O
Evaluating the given integral using the substituting method as shown.
x=In{5) 3e2 dx Let u 2x x=u/2 du /2{On differentiating both sides dr Also at x 0,u = 0 and at x = In (5),u = 2ln(5 Substitute all these values in the given integral, it gives 1 21n(5) edu 2 x=In(5) 3e2 dx 3
Solve as shown...
3 2 In(5) 2 In( 5) 3- {fe'dr = e edu 2 du 3 e" 10 2 Im(5) е -e) _ 2 3 In(5) {alnx=Inx 1nx = X 2(25-1) 3 24 2 = 36
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