Question

Asked Nov 9, 2019

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Evaluate the surface integral.

The double integral over S (xz) dS, S is the part of the plane 2x+2y+z=4 that lies in the first octant.

Step 1

Evaluate the surface integral for the function

2x+2y+z=4

Step 2

Rewrite the given equation 2x+2y+z=4 as x/2+y/2+z/4=1

Here S is the triangular region with vertices (2,0,0),(0,2,0),(0,0,4)

Choose x,y as perimeter and the domain for the perimeter in the triangular region with vertices (2,0,0),(0,2,0),(0,0,4)is

Step 3

Calculate the surfa...

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