eveattనిలికంలక931a Paut blad16. Challenge Problem: Assuming you weresuccessful with the previous question, calculate2-1/4"the short length of the bend in the 2-1/4 inchdiameter pipe (?), rounded to the nearest 16thof an inch. Hint: You have to work your way3-1/4"2-1/4"around the pipe, finding angle measures and35side lengths as you go, as illustrated by thedashed lines.122

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Asked Oct 15, 2019
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I tried to send this problem together with the previous one(no.15). Fisrt time it was rejected, saying that it is Mechanical Enigineering (this is form Math E: Practical Math).  Now, I was told by who solved Problem 15 to resubmit Problem 16 as a separate question. 

Thank you.

eveatt
నిలికంలక
931
a Pau
t blad
16. Challenge Problem: Assuming you were
successful with the previous question, calculate
2-1/4"
the short length of the bend in the 2-1/4 inch
diameter pipe (?), rounded to the nearest 16th
of an inch. Hint: You have to work your way
3-1/4"
2-1/4"
around the pipe, finding angle measures and
35
side lengths as you go, as illustrated by the
dashed lines.
122
help_outline

Image Transcriptionclose

eveatt నిలికంలక 931 a Pau t blad 16. Challenge Problem: Assuming you were successful with the previous question, calculate 2-1/4" the short length of the bend in the 2-1/4 inch diameter pipe (?), rounded to the nearest 16th of an inch. Hint: You have to work your way 3-1/4" 2-1/4" around the pipe, finding angle measures and 35 side lengths as you go, as illustrated by the dashed lines. 122

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Step 1

Note that this question is related to Q 15 since in the question the values of x and y were already been calculated. So, you were supposed to upload the Q15 (with the values of x and y) and Q16 with the specification to solve Q16 in the comment box. So, this time we are solving but next time onwards kindly follow up how to upload related questions like mentioned above.

Step 2

Let us do a little modification in the given problem to solve the problem in a simpler way.

2-1/4
55 R
350
P
м
1.86412
3-1/4
2-1/4"
y
35
A
В
2.66224
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2-1/4 55 R 350 P м 1.86412 3-1/4 2-1/4" y 35 A В 2.66224

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Step 3

From the above figure it can be noticed that ∠QPR = 35o, ∠QRP = 55o and CN = y inch. Here, we will take 2-1/4” as...

Notice triangle ABC:
sin 350
св
у
АC
3.25
=>y = sin 35° x 3.25
=>y 1.86412
Again,
АВ
x
cos 350
АС
3.25
=> x = cos 35° x 3.25
=> x = 2.44224
help_outline

Image Transcriptionclose

Notice triangle ABC: sin 350 св у АC 3.25 =>y = sin 35° x 3.25 =>y 1.86412 Again, АВ x cos 350 АС 3.25 => x = cos 35° x 3.25 => x = 2.44224

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