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Example 11Content Objective: General Chemistry/Reactions and Reaction Mechanisms/StoichiometryFor the reaction below, how much heat would be generated from 10.0 grams (g) of methane32.0 g](CH4) reacting with 64.0 g of oxygen? [MW (CH4) 16.0 g; MW (O2)CH4 (g) +202 (g)CO2 (g)+2H20 (g) AH =-890.3 kJcomplete dsirion ef 34.0 ans ofeoompe120)-28.02 bole, and M0)-2.02 a/ mol02 100016.ormeHow A. 5.56 kJВ. 556 kJС. 1,391 kJD. 8,903 kJ

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Example 11
Content Objective: General Chemistry/Reactions and Reaction Mechanisms/Stoichiometry
For the reaction below, how much heat would be generated from 10.0 grams (g) of methane
32.0 g]
(CH4) reacting with 64.0 g of oxygen? [MW (CH4) 16.0 g; MW (O2)
CH4 (g) +202 (g)
CO2 (g)+2H20 (g) AH =-890.3 kJ
complete dsirion ef 34.0 ans of
eoompe
120)-28.02 bole, and M0)-2.02 a/ mol
02 100016.
orme
How A. 5.56 kJ
В. 556 kJ
С. 1,391 kJ
D. 8,903 kJ
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Example 11 Content Objective: General Chemistry/Reactions and Reaction Mechanisms/Stoichiometry For the reaction below, how much heat would be generated from 10.0 grams (g) of methane 32.0 g] (CH4) reacting with 64.0 g of oxygen? [MW (CH4) 16.0 g; MW (O2) CH4 (g) +202 (g) CO2 (g)+2H20 (g) AH =-890.3 kJ complete dsirion ef 34.0 ans of eoompe 120)-28.02 bole, and M0)-2.02 a/ mol 02 100016. orme How A. 5.56 kJ В. 556 kJ С. 1,391 kJ D. 8,903 kJ

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Step 1

Determine limitin...

10 g
Mass
0.623 mol
No. of moles of CH
=
16.04 g/mol
Molar mass
64.0 g
=2 mol
No. of moles of O2
=
32.00 g/mol
1 mole CH reacts with 2 mol O,
2 mol O2
1 mol CH
0.623 mol CH4 x
No. of moles of O, that needs to reacts with 0.623 mol CH
4
1.246 mol CH
4
No.of mol CH, <No.of mol of O,
Limiting reagent = CH
4
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10 g Mass 0.623 mol No. of moles of CH = 16.04 g/mol Molar mass 64.0 g =2 mol No. of moles of O2 = 32.00 g/mol 1 mole CH reacts with 2 mol O, 2 mol O2 1 mol CH 0.623 mol CH4 x No. of moles of O, that needs to reacts with 0.623 mol CH 4 1.246 mol CH 4 No.of mol CH, <No.of mol of O, Limiting reagent = CH 4

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