EXAMPLE 8 Find the absolute maximum and minimum values of the function below. F(x) = x³ - 3x² + 2 (- 4), we can use the Closed Interval Method: SOLUTION Since fis continuous on f(x) = x³ - 3x2 + 2 F'(x) = |, that is, x = 0 or x =| Since f'(x) exists for all x, the only critical numbers of f occur when f'(x) = [ numbers lies in (- 4). The values of f at these critical numbers are Notice that each of these critical (0) = | and f(2) = | The values of f at the endpoints of the interval are and f(4) = Comparing these four numbere we see that the ahsolute mavimum value is ff4) and the ahsolute minimum value is f2)
EXAMPLE 8 Find the absolute maximum and minimum values of the function below. F(x) = x³ - 3x² + 2 (- 4), we can use the Closed Interval Method: SOLUTION Since fis continuous on f(x) = x³ - 3x2 + 2 F'(x) = |, that is, x = 0 or x =| Since f'(x) exists for all x, the only critical numbers of f occur when f'(x) = [ numbers lies in (- 4). The values of f at these critical numbers are Notice that each of these critical (0) = | and f(2) = | The values of f at the endpoints of the interval are and f(4) = Comparing these four numbere we see that the ahsolute mavimum value is ff4) and the ahsolute minimum value is f2)
Functions and Change: A Modeling Approach to College Algebra (MindTap Course List)
6th Edition
ISBN:9781337111348
Author:Bruce Crauder, Benny Evans, Alan Noell
Publisher:Bruce Crauder, Benny Evans, Alan Noell
Chapter5: A Survey Of Other Common Functions
Section5.4: Combining And Decomposing Functions
Problem 14E: Decay of Litter Litter such as leaves falls to the forest floor, where the action of insects and...
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