Question
Asked Nov 17, 2019
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Excess Na2SO4(aq) is added to a 4.97×102 mL sample of industrial waste containing Ba2+ ions. If 40.5 g of BaSO4(s) are precipitated from the reaction, what was the molar concentration of Ba2+ in the original sample?

Ba2+(aq)+ Na2SO4(aq) --> BaSO4(s) + 2Na+(aq) 

 

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Expert Answer

Step 1

Excess Na2SO4(aq) is added to a 4.97×102 mL sample of industrial waste containing Ba2+ ions. If 40.5 g of BaSO4(s) are precipitated from the reaction, the molar concentration of Ba2+ in the original sample is to be calculated.

Step 2

Write a chemical equation showing reaction between Na2SO4 and Ba2+ ions in a solution.

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Ba (aq)NaSo2(aq)BaSO(s) 2Na (aq)

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Step 3

Calculate the moles of BaSO4 precipitated -

Mass of BaSO4 precipitated = 40.5 ...

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Mass of BaSO precipitated Molar mass of BaSO 40.5 g Moles of BaSO precipitated 233.38 g/mol :. Moles of BaSO, precipitated = 0.174 moles

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