EXERCISES Cu +4 HNO3 Cu(NO3)2+ 2 H20 +2NO2 DHowmany grams of NO2 can be made from 1.4 moles of copper? -1241 c) How many moles of H20 can be made from 8.0 mL of 16 M HNO3? 0.OG4mol H G 2. How many grams of HCI are present in 45.0 mL of 12.0 M HCI solution? 6 A 2 2 3 16.2 grams of ZnO are reacted with 45.0 mL of 6.0 M HCI solution. a) Write a balanced equation for the reaction. ZnOt2HC 2ncla tHa0 b) Which reactant is the limiting reagent? Must calculate. HcA c) Calculate the theoretical yield (grams) of salt produced. 1S 49 2ncls d) If 0.105 moles of salt are produced, what is the % yield? 77.77.

EXERCISES Cu +4 HNO3 Cu(NO3)2+ 2 H20 +2NO2 DHowmany grams of NO2 can be made from 1.4 moles of copper? -1241 c) How many moles of H20 can be made from 8.0 mL of 16 M HNO3? 0.OG4mol H G 2. How many grams of HCI are present in 45.0 mL of 12.0 M HCI solution? 6 A 2 2 3 16.2 grams of ZnO are reacted with 45.0 mL of 6.0 M HCI solution. a) Write a balanced equation for the reaction. ZnOt2HC 2ncla tHa0 b) Which reactant is the limiting reagent? Must calculate. HcA c) Calculate the theoretical yield (grams) of salt produced. 1S 49 2ncls d) If 0.105 moles of salt are produced, what is the % yield? 77.77.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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3.The following reaction takes place as represented by the balanced chemical equation below: Na2SO4 (aq) + Ca(NO3)2 (aq) --> CaSO4 (s) + 2 NaNO3 (aq) How many grams of solid CaSO4 would form from combining 22.9 mL of 3.75 M Na2SO4 solution and 38.3 mL of 2.9 M Ca(NO3)2 solution? Numerical answer:
Example: 35.43 mL of 0.254 M sodium hydroxide are combined with 23.31 mL of 0.125 M acetic acid? What is the reaction happening here? Which reagent is limiting?
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(A) Sample Problem: A 12.1 Moles NaOH solution means there are 12.1 moles of NaOH in liter of solution. Preparation of 12.1 M NaOH: Step 1: Determine the number of grams of NaOH in 12.1 moles of NaOH solution 1 mole of NaOH = ___g of NaOH, in 12.1 moles of NaOH, there are ___g of NaOH. Show the calculation to obtain the number of grams of NaOH Step 2: Now weigh -___of NaOH (resulted mass of NaOH in step 1) using balance. Step 3: Put the ___g of NaOH in a beaker, then add enough water to make it 1 Liter of solution. Stir the solution until NaOH is completely dissolved. (B) Sample Problem: A chemist prepares a solution by dissolving .8 mole of NaOH in water to give a 50 ml solution. What is the molarity of this solution? (C) Sample problem: What is molality of a solution prepared by dissolving 20g MgCl2 in 250 g water? (D) Sample Problem: What is the mole fraction of the particles contained in a 25% sucrose ?
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