EXPERIMENT 2: CHEMICAL EQUILIBRIUM Molarity of sodium hydroxide solution =_ _1.4679 Average titre Ke (mL) Vial NaOH titre number (mL) Initial Final Net 1 0.16 10.86 NOT 10.86 21.46 APPLICABLE 3 0.05 25.95 0.07 26.17 5 0.03 16.63 6. 16.63 32.26 7 0.09 25.19 0.07 24.95 Remarks for calculations 1. The average volume of NaOH solution from vials 1 and 2 represents the amount of HCl added. This volume has to be subtracted from the average volume of NaOH solution for vials 4,5,6,7, and 8 to get the volume of NaOH that corresponds to the acetic acid alone. 2. The concentration of water is included in the equilibrium calculations 3. The amount of water in each vial is equal to what we added plus the water that came with the HCI. CALCULATIONS

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
ChapterA1: Evaluation Of Analytical Data
Section: Chapter Questions
Problem A1.22QAP
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Ex2:

EXPERIMENT 2: CHEMICAL EQUILIBRIUM
Molarity of sodium hydroxide solution =_
_1.4679
Average titre Ke
(mL)
Vial
NaOH titre
number
(mL)
Initial
Final
Net
1
0.16
10.86
NOT
10.86
21.46
APPLICABLE
3
0.05
25.95
0.07
26.17
5
0.03
16.63
6.
16.63
32.26
7
0.09
25.19
0.07
24.95
Remarks for calculations
1. The average volume of NaOH solution from vials 1 and 2 represents the amount of HCl
added. This volume has to be subtracted from the average volume of NaOH solution for
vials 4,5,6,7, and 8 to get the volume of NaOH that corresponds to the acetic acid alone.
2. The concentration of water is included in the equilibrium calculations
3. The amount of water in each vial is equal to what we added plus the water that came with
the HCI.
CALCULATIONS
Transcribed Image Text:EXPERIMENT 2: CHEMICAL EQUILIBRIUM Molarity of sodium hydroxide solution =_ _1.4679 Average titre Ke (mL) Vial NaOH titre number (mL) Initial Final Net 1 0.16 10.86 NOT 10.86 21.46 APPLICABLE 3 0.05 25.95 0.07 26.17 5 0.03 16.63 6. 16.63 32.26 7 0.09 25.19 0.07 24.95 Remarks for calculations 1. The average volume of NaOH solution from vials 1 and 2 represents the amount of HCl added. This volume has to be subtracted from the average volume of NaOH solution for vials 4,5,6,7, and 8 to get the volume of NaOH that corresponds to the acetic acid alone. 2. The concentration of water is included in the equilibrium calculations 3. The amount of water in each vial is equal to what we added plus the water that came with the HCI. CALCULATIONS
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