Question
Asked Oct 17, 2019

The force acting on a particle varies as shown in the figure below.

a) Find the work done by the force on the particle as it moves from x = 0 m to x = 8 m.

b) Find the work done by the force on the particle as it moves from x = 8 m to x = 12 m.

c) Find the work done by the force on the particle as it moves from x = 0 m to x = 12 m.

F (N)
6
4
x (m)
8 10
2 4
6
-2
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F (N) 6 4 x (m) 8 10 2 4 6 -2

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check_circleExpert Solution
Step 1

Work done by the force on the particle is equal to area under the force versus distance graph .

(a) Write the expression for work done by the force on the particle from x=0m to x=8m from the graph .

(6N)(8m)
2
- 24J
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(6N)(8m) 2 - 24J

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Step 2

(b) Write the expression for work done by the force on ...

1
(-3N)(4m)
2
=-6J
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1 (-3N)(4m) 2 =-6J

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Work,Power and Energy

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