f we need to find the equation of a plane when given a point in 3-dimensions and two planes that intersect in a line that is contained in the objective plane, how do we find the line of intersection of the two given planes and then proceed to find two points on that line so that we may find the equation of the objective plane with three points and the cross product (to find the normal plane)? Please do an example with point (3, 1, 4) and planes x + 2y + 3z = 1 and 2x - y + z = -3, and please explain all of the steps and use typefont. Thank you!

Linear Algebra: A Modern Introduction
4th Edition
ISBN:9781285463247
Author:David Poole
Publisher:David Poole
Chapter2: Systems Of Linear Equations
Section2.2: Direct Methods For Solving Linear Systems
Problem 47EQ
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If we need to find the equation of a plane when given a point in 3-dimensions and two planes that intersect in a line that is contained in the objective plane, how do we find the line of intersection of the two given planes and then proceed to find two points on that line so that we may find the equation of the objective plane with three points and the cross product (to find the normal plane)? Please do an example with point (3, 1, 4) and planes x + 2y + 3z = 1 and 2x - y + z = -3, and please explain all of the steps and use typefont. Thank you!

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