Question
Asked Oct 7, 2019
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Please explain on number 11 how to go from step 5 to step 6 (labeled). I understand that you are factoring an ln(t) out, but I am confused with what happens to the denominator of the fraction. 

 

The answer in my textbook has the form in step 6, but I'm not sure how it works out that way. 

FCH-nsint
Step 1
FE Int Sint +sin (int
dx
F =dAL)2) inct) Sint+ Cost) in-
dx
Step 2
F'C+ 2Iht)
Cos(+)CInt)
Shep ३
sint
Int)
h वेस
FI
2(Intt cas)int
tncts
step 5
20nCt) Sint
+Cos Int
inct)
Step F Int)
2 SiA
+Cos CInt
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FCH-nsint Step 1 FE Int Sint +sin (int dx F =dAL)2) inct) Sint+ Cost) in- dx Step 2 F'C+ 2Iht) Cos(+)CInt) Shep ३ sint Int) h वेस FI 2(Intt cas)int tncts step 5 20nCt) Sint +Cos Int inct) Step F Int) 2 SiA +Cos CInt

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Expert Answer

Step 1

The given funct...

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F (t)=(In(t)) sint

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Tagged in

Math

Calculus

Derivative