Question
Asked Nov 8, 2019
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29.7       The current in the long, straight wire AB shown in Fig. E29.7 is upward and is increasing steadily at a rate di/dt.

(a) At an instant when the current is i, what are the magnitude and direction of the field B at a distance  r to the right of the wire?

(b) What is the magnetic flux through the narrow, shaded strip?

(c) What is the total flux through the loop?

(d) What is the induced emf in the loop?

(e) Evaluate the numerical value of the induced emf if a = 12.0 cm, b = 36.0 cm, L = 24.0 cm, and di/dt = 9.60 A/s.

Figure E29.7
В
- dr
a
A
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Figure E29.7 В - dr a A

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Expert Answer

Step 1
Given Info: The distance between the current carrying conductor and
the loop on left side is a. The distance between the current carrying
conductor and the loop on right side is b. The length of the loop is L
The magnetic constant is uo.
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Given Info: The distance between the current carrying conductor and the loop on left side is a. The distance between the current carrying conductor and the loop on right side is b. The length of the loop is L The magnetic constant is uo.

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Step 2
D
dl
dr
Magnetic field
into the page
long straight
conductor
Figure
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D dl dr Magnetic field into the page long straight conductor Figure

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Step 3
Refer figure.1. Consider a straight conductor CD carrying a current (i)
along z-direction. The magnetic field Bat a distance p from the straight
conductor on its perpendicular bisector at a point P
The straight conductor is along the zaxis with its lower end Cand upper
end Drespectively subtending angles a1 and a
at point P.
Formula to calculate the magnetic field intensity using Biot-Savart's Law
is,
id l x R
Н.
4т R
i is the current carrying in the straight conductor,
R is the distance vector from the differential length on the
conductor and the magnetic field,
.Ris the magnitude of the distance vector from the differential
length on the conductor and the magnetic field,
dl is the differential length on the straight conductor
help_outline

Image Transcriptionclose

Refer figure.1. Consider a straight conductor CD carrying a current (i) along z-direction. The magnetic field Bat a distance p from the straight conductor on its perpendicular bisector at a point P The straight conductor is along the zaxis with its lower end Cand upper end Drespectively subtending angles a1 and a at point P. Formula to calculate the magnetic field intensity using Biot-Savart's Law is, id l x R Н. 4т R i is the current carrying in the straight conductor, R is the distance vector from the differential length on the conductor and the magnetic field, .Ris the magnitude of the distance vector from the differential length on the conductor and the magnetic field, dl is the differential length on the straight conductor

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