
College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Figure P19.35a is a diagram of a device called a velocity selector, in which particles of a specific velocity pass through undeflected while those with greater or lesser velocities are deflected either upwards or downwards. An electric field is directed perpendicular to a magnetic field, producing an electric force and a magnetic force on the charged particle that can be equal in magnitude and opposite in direction (Fig. P19.35b) and hence cancel. Show that particles with a speed of v = E/B will pass through the velocity selector undeflected.
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution
Trending nowThis is a popular solution!
Step by stepSolved in 4 steps with 4 images

Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- An alien from a planet in the galaxy M31 (Andromeda) has a ray gun that shoots protons at a speed of 2.0 × 10^5 m/s. Design a magnetic shield that will deflect the protons away from your body. A) Suppose that the magnetic field has horizontal direction and you want to deflect the beam through a path with radius R = 2.0 m as shown in (Figure 1). Find the field strength needed to achieve the desired deflection. The mass of a proton is 1.67× 10^−27 kg and its charge is 1.6× 10^−19 C. B) What is the direction of the magnetic field in the region defined in (Figure 1), that would cause the deflection shown for the proton beam? along the path of the proton beam into the page toward the center of the curved path out of the page C)What is the direction of the magnetic force in the region defined in (Figure 1), that would cause the deflection shown for the proton beam? along the path of the proton beam into the page toward the center of the curved path out of the pagearrow_forwardA magnetic field has a magnitude of 0.0017 T, and an electric field has a magnitude of 4.7 x 103 N/C. Both fields point in the same direction. A positive 2.1-μC charge moves at a speed of 3.1 x 106 m/s in a direction that is perpendicular to both fields. Determine the magnitude of the net force that acts on the charge. B Number i 9 V 90° Units Earrow_forwardA proton is projected perpendicularly into a magnetic field that has a magnitude of 0.23 T. The field is then adjusted so that an electron will follow a circular path of the same radius when it is projected perpendicularly into the field with the same velocity that the proton had. What is the magnitude of the field used for the electron? Be=arrow_forward
- A powerful, superconductive wire carries a 5000A current directly out of this screen. An electron is travelling parallel to the wire with a speed of 5E8 m/s, in the same direction as the current. the electron is 50.0 (micrometer) to the right of the wire. A) What is the magnitude and direction of the Magnetic field due to the superconductor at the location of the electron? B) What is the magnitude and direction of the force acting on the electron due to the superconductor's magnetic field?arrow_forwardA singularly-charged ion (i.e. a neutral atom which has gained one electron) with kinetic energy of 7x10−15 J follows a circular path of radius 0.6m when placed in a magnetic field of 0.5T. (Note that the charge of an electron is e = 1.6 x 10−19 C.) a) Using the fact that the ion is going in a circular motion in a magnetic field, what is the ion’s momentum (in kg.m/s)? b) What is the ion’s speed (in m/s)? c) What is the ion’s mass (in kg)? d) An electric field is added to the experiment and adjusted so that the ion passes through without any deflection. What is the magnitude of this electric field (in T)?arrow_forwardA proton, that is accelerated from rest through a potential of 55 kV enters the velocity filter, consisting of a parallel-plate capacitor and a magnetic field, shown below. What is the proton's speed? Take mp 1.67 × 10-27 kg and e = = 1.6 × 10-¹⁹ C. P = E The magnetic field, B = (x) B (x) The speed, v = The E-field between the plates is 2.2 × 105 N/C. What B-field is required so that the protons are not deflected? Units Select an answer ✓ X Units Select an answer ✓arrow_forward
- A beam of electrons is simultaneously influenced by an homogeneous electric field of 15600 V/m and by a homogeneous magnetic field of 4.62 x 10-3 T. Assume that both fields are perpendicular to the electron beam and to each other. Both fields have to be oriented such that they produce no deflection of the electron beam. a) Draw the relative orientations of the vectors v, E, and B and also the forces of FE and FB .b) Determine the speed of the electrons such that there is no deflection of the electron beam. c) When the electric field is switched off, what is the radius and the period of the electron orbit?arrow_forwardWhen a proton has a velocity of (2i+8j)*10^6 m/s , it experiences a force of -1.6*10^-13k N. . In a second experiment with the same B field, the particle is moving along the + z-axis and under these new conditions it experiences a force along the + x-axis . What is the magnetic field? answer should be in (i,j,k)arrow_forwardA charged particle moves through a velocity selector at constant velocity. The velocity selector is configured with "crossed" electric and magnetic fields of magnitude E = 1.50 x 104 N/C and B = 0.4 T. %3D Hint a. What is the velocity of the charged particle? Velocity of the charged particle is x 104 m/s. b. When the electric field is turned off, the charged particle travels in a circular path of radius 6 mm, as it travels through the magnetic field (still at B = 0.4 T). What is the mass-to-charge ratio of the particle? Hint for (b) Mass-to-charge ratio of the part is kg/C. (Use the "E" notation to enter your answer in scientific notation. For example, to enter 3.14 × 10´ 12".) - 12 enter "3.14E-arrow_forward
arrow_back_ios
arrow_forward_ios
Recommended textbooks for you
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON

College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning

University Physics (14th Edition)
Physics
ISBN:9780133969290
Author:Hugh D. Young, Roger A. Freedman
Publisher:PEARSON

Introduction To Quantum Mechanics
Physics
ISBN:9781107189638
Author:Griffiths, David J., Schroeter, Darrell F.
Publisher:Cambridge University Press

Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning

Lecture- Tutorials for Introductory Astronomy
Physics
ISBN:9780321820464
Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina Brissenden
Publisher:Addison-Wesley

College Physics: A Strategic Approach (4th Editio...
Physics
ISBN:9780134609034
Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field
Publisher:PEARSON