Question
Asked Dec 23, 2019
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A 1.00-kg beaker containing 2.00 kg of oil (density = 916 kg/m3 ) rests on a scale. A 2.00-kg block of iron is suspended from a spring scale and is completely submerged in the oil (Fig. P9.31). Find the equilibrium readings of both scales.

Figure P9.31
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Figure P9.31

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Expert Answer

Step 1

In equilibrium, the sum of all force acting on the block of wood is

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EF, = F, + Fgu – m28 [1] [2] ron upper 0 = (mcg - PaVica8)= F ait' iron "iron upper

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Step 2

Use the equation (2) to solve for the equil...

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Poil [3] F. upper 1- m. Piron 916 kg /m 7.86×10 kg/m² (2.00kg)(9.8m/s³) = 17.31N ||

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Science

Physics

Newtons Laws of Motion