Fill in each blank with appropriate comments to demonstrate your understanding of Assembly@GO@Data Section@.data.balign 4string: .asciz "\na +h4a: .word 33b: .word 44c:.word 0600Code Section.text.global main.extern printfmain:1dr r1, a1dr r1, [1]1dr r2, -b1dr r2, [2]add r1, r1, r21dr r2, =cstr r1, [2]push {ip, lr}1dr1dr r1, [2]bl printfpop56GGGOOO78123SEall 101112"%d\n"13.34(ip, pc)141516re, -string@18@1992017

Introduction Assembly language programmes are made up of a series of source statements. Every source…

Fill in each blank with appropriate comments to demonstrate your understanding of Assembly Data Section .data .balign 4 string: .asciz "\na + a: .word 33 b: .word 44 c: .word 0 Code Section .text .global main .extern printf main: ldr ri, a 1dr r1, [1] 1dr r2, -b 1dr r2, [2] add r1, r1, r2 1dr r2, =c str r1, [2] 1dr 1dr r1, [2] push {ip, lr) re, bl printf pop (B) 4 5 6 GGGGGG 7 8 2 3 {ip, pc} "%d\n" 11 12 13 14 15 16 10 string 18 19 @20 17

Fill in each blank with appropriate comments to demonstrate your understanding of Assembly Data Section .data .balign 4 string: .asciz "\na + a: .word 33 b: .word 44 c: .word 0 Code Section .text .global main .extern printf main: ldr ri, a 1dr r1, [1] 1dr r2, -b 1dr r2, [2] add r1, r1, r2 1dr r2, =c str r1, [2] 1dr 1dr r1, [2] push {ip, lr) re, bl printf pop (B) 4 5 6 GGGGGG 7 8 2 3 {ip, pc} "%d\n" 11 12 13 14 15 16 10 string 18 19 @20 17

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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The following data segment starts at memory address 1000h (hexadecimal) .data printString BYTE "ASSEMBLY IS FUN",0 moreBytes BYTE 25(DUP)0 dateIssued DWORD ? dueDate DWORD ? elapsedTime Word ? What is the hexadecimal address of dueDate ? a. 1045h b. 1029h c.1010h d. 102Dh
convert this code to java language /* OPERATING SYSTEMS LAB PROJECT* AKASH JAIN* 179303013* DESIGNING A VIRTUAL MEMORY MANAGER*/ #include<stdio.h>#include<stdlib.h>#include<string.h> const int VM_SIZE=256;const int PAGE_SIZE=256;const int TLB_SIZE=16;const int MM_SIZE=256; int main(int argc, char* argv[]){FILE *fd;if(argc<2){printf("NOT ENOUGH AGRUMENTS\n EXITING\n");return 0;}fd=fopen(argv[1],"r");if(fd==NULL){printf("ERROR OPENING FILE\n FILE FAILED TO OPEN\n");return 0;}char *value=NULL;size_t len=0;ssize_t read;long long page_no,offset,page_table,totalhits=0,fault=0,pages=0;int qp=0; //to maintain the queue positionint physicalad=0,frame,logicalad;int tlb[TLB_SIZE][2];int pagetable[PAGE_SIZE]; memset(tlb,-1,TLB_SIZE*2*sizeof(tlb[0][0]));memset(pagetable,-1,sizeof(pagetable));int mask=255,mask1=62580,i,hit;while((read=getline(&value,&len,fd))!=-1){pages++;//get page number and offset from logical…
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PLEASE ONLY USE 8051 MICROCONTROLLER (AT89C51 FOR EXAMPLE) AND ASSEMBLY LANGUAGE, NOT ANY OTHER MICROCONTROLLER OR LANGUAGE, THANKS. I ADDED MY TRY OF CODE (IT BASICALLY COUNTS FROM 11 TO 00.) I DONT WANT SOLUTION IN THIS CODE FORMAT: DISP MACRO MSG LEA DX , MSG MOV AH , 09H INT 21H END DATA SEGMENT MSG DB "THE REMAINING TIME IS: $" DATA ENDS CODE SEGMENT ASSUME DS:DATA , CS : CODE START:MOV AX , DATA MOV DS , AX DISP MSG MOV AH , 2CH INT 21H MOV AL , CH MOV BX , AX CALL SHOW MOV DL , ' : ' MOV AH , 02H SCREEN INT 21H MOV AL , CL .........
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Give an example of how to reduce the size of the translation table in flash storage, which is often used to convert very large ranges of consecutive logical page numbers into consecutive physical page numbers. Flash memory:
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