Question

Asked Sep 23, 2019

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Step 1

Horizontal tangent line is located where the derivative of the function takes zero value.

Here the function is **f (x) = x ^{3}-5x^{2}-6x+7**

For finding the value of **x** use the derivate of the function to locate the zero.

Step 2

Now the derivative of the function:

Step 3

Now for finding the value of **x** put **f’(x) =0 .**

**3x2-10x-6=0**

It’s a quadratic equation of the form **ax2+bx+c =0** so the solutions are

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