Question

Asked Mar 10, 2019

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Find an equation of the parabola y = ax^{2} + bx + c that passes through (0,1) and is tangent to the line y = x-1 at (1,0).

Step 1

Since, the parabola passes through (0,1) ,so,we substitute x=0, y=1 ,to get c=1

Step 2

Now, it is given the parabola also passes through (1,0) and the slope of tangent at (1,0) is 1, Using these two conditions, we get two equations

Step 3

By subtracting the two equations , we get value of a, then by subs...

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