Question
Asked Sep 28, 2019
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Find an equation of the tangent line to the curve at the given point 

 

y= xe^-x^2 , (0,0)

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Step 1

Slope:

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dy Slope of the tangent m d\At (0,0) d (xe" -x) At (0,0) (xe +e-2x (0,0) -(0+e-2(0)) =1

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Tagged in

Math

Calculus