Question
Asked Oct 23, 2019
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Find an equation of the tangent line to the curve y=8ln((x^3)-26) at the point (3,0).

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Expert Answer

Step 1

To determine equation of tangent line at given point.

Step 2

Given:

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y 8ln(x-6 - 2 Point:(3,0)

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Step 3

Concept Used:

The slope of the tangent to the graph of f(x) is given by the first order derivative of the function f(x), that is, slope of tangent = ...

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y-b f(a)(x-a)

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Tagged in

Math

Calculus