Find an equation of the tangent line to the graph at the given point. (x + 2)? + (y – 3)² - 37, (-1, 9) Circle (-1, 9) 2

Q Search L W Find the equation of the curve whose slope is √√6x-3 and passes through (2, -1).

Use the graph below to determine the equation of the circle in ​(a)​ center-radius form and ​(b) general form.                   -1010-1010(2,6)(2,0)(5,3)(-1,3)          A coordinate system has a horizontal x-axis labeled from negative 10 to 10 in increments of 1 and a vertical y-axis labeled from negative 10 to 10 in increments of 1. A circle has a center at (2, 3) and passes through the labeled plotted points (5, 3), (2, 0), (negative 1, 3), and (2, 6).   ...   Question content area right Part 1 a. Type the equation in​ center-radius form.   enter your response here ​(Simplify your​ answer.) Part 2 b. Type the equation in general form.   enter your response here ​(Simplify your​ answer.)

if point (20,10) is on the graph of y=f(x). How would you Find the corresponding point on the graph of y=-2f(2(x+1))+6?

Find X and Y intercepts of the given equation. Sketch the graph of the equation.

Find the intercepts of y=−2x−2y=-2x-2. Enter answers as points (x,y)(x,y) Using the intercepts from above draw the graph of y=−2x−2y=-2x-2