Question
Asked Oct 14, 2019
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Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point.
(x − y − 1)3 = x; (1, −1) 
 
y=
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Expert Answer

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Step 1

Given:

The equation of the plane is: (x-y-) = x
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The equation of the plane is: (x-y-) = x

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Step 2

Differentiate with respect to x as follows.

3
dc
dy
1
=1
dx
3(х -у-1)
dy
1-
1
3 (х-у-1)*
dx
1
=1
3(х-у-1)°
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3 dc dy 1 =1 dx 3(х -у-1) dy 1- 1 3 (х-у-1)* dx 1 =1 3(х-у-1)°

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Step 3

At (1, –1), the deri...

dy
3(1-(-1)-1)
1
2
1
=1-
3 (1)
3
2
3
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dy 3(1-(-1)-1) 1 2 1 =1- 3 (1) 3 2 3

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Tagged in

Math

Calculus

Derivative